17P1Q03

3 C

Method 1

Distance travelled can be obtained from area under the speed-time graph.

By inspection, the cyan area is 3 times the green area.

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Method 2

$\displaystyle (s=ut+\frac{1}{2}a{{t}^{2}})$

Distance travelled between 0 s and 6 s $\displaystyle =0+\frac{1}{2}a{{(6)}^{2}}=18a$

Distance travelled between 0 s and 12 s $\displaystyle =0+\frac{1}{2}a{{(12)}^{2}}=72a$

Distance travelled between 6 s and 12 s $\displaystyle =72a-18a=54a$

ratio $\displaystyle =54a\div 18a=3$

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#kinematics

#kineGraph

xmPhysics