23P2Q07

7ai)

Photoelectric effect

7aii)

Double slit interference pattern

7bi)

+ on the left, – on the right.

7bii)

$\displaystyle \begin{aligned} K{{E}_{\max }}&=hf-\Phi \\ e{{V}_{s}}&=12.4e-4.2e \\ {{V}_{s}}&=8.2\text{ V} \end{aligned}$

7biii)

Increasing the intensity only increases the number of photons per unit time.

The energy of each individual photon remains at 12.4 eV.

Since each photoelectron is liberated by the energy of one photon, its KE_max is not increased.

7c)

xmPhysics