24P1Q01

1 A

$\displaystyle \begin{aligned} A&=\pi {{r}^{2}} \\ &=\pi {{(4\times {{10}^{2}}\times {{10}^{6}})}^{2}} \\ &=5.02\times {{10}^{17}}\text{ }{{\text{m}}^{2}} \end{aligned}$

Option A: $\displaystyle 5\times {{10}^{-1}}\text{ G}{{\text{m}}^{2}}=5\times {{10}^{-1}}\times {{({{10}^{9}})}^{2}}\text{ }{{\text{m}}^{2}}=5\times {{10}^{17}}\text{ }{{\text{m}}^{2}}$

Option B: $\displaystyle 5\times {{10}^{2}}\text{ G}{{\text{m}}^{2}}=5\times {{10}^{2}}\times {{({{10}^{9}})}^{2}}\text{ }{{\text{m}}^{2}}=5\times {{10}^{20}}\text{ }{{\text{m}}^{2}}$

Option C: $\displaystyle 5\times {{10}^{-2}}\text{ T}{{\text{m}}^{2}}=5\times {{10}^{-2}}\times {{({{10}^{12}})}^{2}}\text{ }{{\text{m}}^{2}}=5\times {{10}^{22}}\text{ }{{\text{m}}^{2}}$

Option D: $\displaystyle 5\times {{10}^{0}}\text{ T}{{\text{m}}^{2}}=5\times {{10}^{0}}\times {{({{10}^{12}})}^{2}}\text{ }{{\text{m}}^{2}}=5\times {{10}^{24}}\text{ }{{\text{m}}^{2}}$

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24P1Q01

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