3 C
Method 1
Solve for the time to reach the peak tp using the vertical motion.
Time of flight,
Method 2
![\displaystyle \begin{aligned} (s&=ut+\frac{1}{2}a{{t}^{2}}) \\ 0&=15\sin 40{}^\circ {{t}_{f}}-\frac{1}{2}(1.62){{t}_{f}}^{2} \\ 0&={{t}_{f}}[15\sin 40{}^\circ {{t}_{f}}-\frac{1}{2}(1.62){{t}_{f}}] \\ {{t}_{f}}&=0\text{ (rejected) or 11}\text{.9 s} \end{aligned}](https://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cbegin%7Baligned%7D%C2%A0+%C2%A0%28s%26%3Dut%2B%5Cfrac%7B1%7D%7B2%7Da%7B%7Bt%7D%5E%7B2%7D%7D%29+%5C%5C%C2%A0%C2%A00%26%3D15%5Csin+40%7B%7D%5E%5Ccirc+%7B%7Bt%7D_%7Bf%7D%7D-%5Cfrac%7B1%7D%7B2%7D%281.62%29%7B%7Bt%7D_%7Bf%7D%7D%5E%7B2%7D+%5C%5C%C2%A0%C2%A00%26%3D%7B%7Bt%7D_%7Bf%7D%7D%5B15%5Csin+40%7B%7D%5E%5Ccirc+%7B%7Bt%7D_%7Bf%7D%7D-%5Cfrac%7B1%7D%7B2%7D%281.62%29%7B%7Bt%7D_%7Bf%7D%7D%5D+%5C%5C%C2%A0%C2%A0%7B%7Bt%7D_%7Bf%7D%7D%26%3D0%5Ctext%7B+%28rejected%29+or+11%7D%5Ctext%7B.9+s%7D%C2%A0%5Cend%7Baligned%7D&bg=ffffff&fg=000000&s=0&c=20201002)
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3 C
Method 1
Solve for the time to reach the peak tp using the vertical motion.
Time of flight,
Method 2
xmPhysics 
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