24P1Q10

10 A
$\displaystyle \omega =\frac{2\pi }{24\times 3600}=7.272\times {{10}^{-5}}\text{ rad }{{\text{s}}^{-1}}$

$\displaystyle \begin{aligned}a&=r{{\omega }^{2}} \\ &=(1.3\times {{10}^{7}}\div 2){{(7.272\times {{10}^{-5}})}^{2}} \\ &=0.0339\text{ m }{{\text{s}}^{-1}} \end{aligned}$

The acceleration is centripetal, i.e. directed towards the centre of the circular motion.

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