24P1Q13

13 D

Use m to denote the mass of volume V of water.

Method 1

$\displaystyle \frac{4m\times 60+m\times 20}{5m}=52\,{}^\circ \text{C}$

Method 2

$\displaystyle \begin{aligned} \text{heat gained by }m&=\text{heat lost by 4}m \\ mc(T-20)&=4mc(60-T) \\ T-20&=240-4T \\ T&=52\text{ }\!\!{}^\circ\!\!\text{ C} \end{aligned}$

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