How do the passengers not drop out of the car when they are inverted at the top of the loop?

The following video explains why.

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# Roller Coaster

# Water Pail Swung in Vertical Circular

# Ball Swung in Vertical Circle

# Conical Circular Motion

# Centrifugal Force?

# Centripetal Force

# Centripetal Acceleration

# Angular Velocity

Category: 06 Circular Motion

How do the passengers not drop out of the car when they are inverted at the top of the loop?

The following video explains why.

Why doesn’t the water fall out of the bottle?

Let’s consider the water when the bottle is at the top most position. At this instant, the water has a horizontal velocity. The earth’s gravitational pull would have caused the water to continue along a parabolic arc. The bottle, however, intends to follow a circular path. Relative to the circular path of the bottle, the parabolic path of the water would have taken the water out of the bottle through the TOP, not the BOTTOM, thus puncturing the base of the bottle.

Of course, the bottle would not allow itself to be punctured by water. So what it does is to exert a downward normal contact force on the water, just enough to push the water into following the same circular path as the bottle.

The water falls out of the bottle only if it falls faster than the pail. As long as the bottle is swung at a high enough speed, this will not happen. In fact, the bottle must press down on the water to make the water fall faster, as fast as the bottle.

As the ball loses speed, it eventually becomes too slow to complete the loop successfully.

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Why? The next video explains.

All the circular motion featured here have very similar dynamics.

(1) Conical Pendulum

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(2) Flying Chairs

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(3) Airplane turning a horizontal circle

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(4) Cars turning on banked curve

NASCAR race cars do not slow down when they turn. The tracks are banked (slanted) at the bends. Banking allows the cars to utilize the normal contact force that the track surface exerts on the cars to help provide the required centripetal force. This allows NASCAR to turn at full speed. In fact, at particular speed and angles, the cars can negotiate the bends without the tires providing any sideway frictional force at all. The following video explains.

When we see the bodies pinned against the wall, it is tempting to imagine that there are some centrifugal forces pushing those people outward against the wall. But there is none. The motion is fully explained by the **presence of a** **centripetal** **force**, not a centrifugal force.

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The same principle is being applied by these stuntmen. The key to pulling off this stunt successfully is to ride at a high speed. The inertia of the bike (tendency to keep moving straight) causes it to pressed hard against the wall, resulting in a large normal contact force. A large normal contact force is crucial because the amount of friction depends on it. It is the frictional force that holds up the weight of the car.

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Quantitatively, the magnitude of the required centripetal force is related to the speed and radius of circular motion by the formula *F*=*mv*^{2}/*r*.

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For the same *v*, a stronger centripetal force *F* would result in a tighter circular motion (smaller *r*). In the animation below, the objects are experiencing centripetal forces of 4*F*, 2*F* and *F*, resulting in circular motion of radii *R*, 2*R* and 4*R*.

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For the same centripetal force *F*, a lower speed *v* would result in a tighter circular motion (smaller *r*). In the animation below, the objects have speeds of 1/√2 *v*, *v* and √2*v*, resulting in circular motion of radii *R*, 2*R* and 4*R*.

The direction of the velocity continuously change towards the centre of the circle, but the magnitude of the velocity is constant. Uniform circular motion is accelerated motion. The acceleration is in the centripetal direction.

How do the linear velocity *v* and angular velocity *ω* of these two circular motions compare?

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*v*=*rω*

These two circular motions have the same *ω*. The blue one has twice the radius, so its *v* is double that of the red one.

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*ω*=*v*/*r*

These two circular motions have the same *v*. The blue one has twice the radius, so its *ω* is half that of the red one.